(2y^2-x)(x+4y)=0

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Solution for (2y^2-x)(x+4y)=0 equation: 


Simplifying
(2y2 + -1x)(x + 4y) = 0

Reorder the terms:
(-1x + 2y2)(x + 4y) = 0

Multiply (-1x + 2y2) * (x + 4y)
(-1x * (x + 4y) + 2y2 * (x + 4y)) = 0
((x * -1x + 4y * -1x) + 2y2 * (x + 4y)) = 0

Reorder the terms:
((-4xy + -1x2) + 2y2 * (x + 4y)) = 0
((-4xy + -1x2) + 2y2 * (x + 4y)) = 0
(-4xy + -1x2 + (x * 2y2 + 4y * 2y2)) = 0
(-4xy + -1x2 + (2xy2 + 8y3)) = 0

Reorder the terms:
(-4xy + 2xy2 + -1x2 + 8y3) = 0
(-4xy + 2xy2 + -1x2 + 8y3) = 0

Solving
-4xy + 2xy2 + -1x2 + 8y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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